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It means that reading the disassembled code requires us to mentally map %rax not to the return value, but to just another scratch reg. How does that lead to address 0x10c to get a value of 0x11? I just want to read values that are currently in those registers

Beast mode

Rax, rbx, rcx, rdx, rsp But that didn't work for 9 (%rax, %rdx) Rbp, rsi, rdi and print them out, thats it.

In at&t syntax, the instruction

Mov (%rax), %eax # at&t syntax or, equivalently in intel syntax Mov eax, dword ptr [rax] Essentially all x86 chips released in the last decade from amd and intel support this isa Thus (%rax) means to get the value of the pointer currently stored in %rax

What does the star decoration do on that Does that further dereference that value (thus (%rax) is itself a pointer) I'm having trouble googling *( assembly syntax This is x64 assembly generated from gcc 4.8 compiling c++ code.

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And in the similar problem i found here

Hard time understanding assembly language it seems that with 260 (%rcx, %rdx) we needed to convert the value to hexadecimal

Beast mode
raxkingisdead (u/raxkingisdead) - Reddit