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The c++ rand () function gives you a number from 0 to rand_max (a constant defined in <cstdlib>), which is at least 32767 The op's reasoning for trying it was wrong, but had this been necessary, the ub could've been avoided by adding 1.0 instead of 1, which would coerce rand_max to double type and so avoid the integer overflow. (from the c++ documentation) the modulus (%) operator gives the remainder after dividing
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When you use it with rand () you are using it to set an upper limit (n) on what the random number can be. When available, random() does not suffer of this issue. These sequences are repeatable by calling srand() with the same seed value.
Many implementations of rand() cycle through a short list of numbers, and the low bits have shorter cycles
The way that some programs call rand() is awful, and calculating a good seed to pass to srand() is hard Me gustaria si me pudieran explicar bien cual es la diferencia, me confundo mucho con rand y srand, ¿cual es la diferencia He buscado en otros sitios, pero confundo más If you don't call srand before your first call to rand, it's as if you had called srand(1) to set the seed to one.
Y con dado = 1 + rand() % 6 puedo generar un número aleatorio entre 1 y 6 para la variable dado No entendí el razonamiento para llegar a la fórmula de dado pero funciono ¿cómo podría generar un número aleatorio en c con un rango diferente Entre 1 y 9 entre 12 y 21 gracias.
A second lesson is that this shows another way in which <random> is easier to use than rand() and manually computing your own distributions
