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Cin is a blocked input This option resolved my issue! Whatever comes from the keyboard is stored in a buffer

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When you press enter the system passes the buffer to the application code (std::cin code) When using std::getline(std::cin, s) i would get a very messy and i would say, interrupted input when waiting for inputs in a while / for loop Depends on the type of the operand.

79 cin is an object of class istream that represents the standard input stream

It corresponds to the cstdio stream stdin The operator >> overload for streams return a reference to the same stream The stream itself can be evaluated in a boolean condition to true or false through a conversion operator Cin provides formatted stream extraction.

3 there is no close equivalent to cin in c However, you can read things in c using the c standard library, you can look at the relevant part here (cstdio reference). I am currently reading in with std::cin >> for the strings i expect to be single words and getline(std::cin, string) for the strings with spaces I am not getting the right output, though.

The problem is that cin >> y is only storing the first word of the line the user types, the asker wants to know how to store the entire line in y, such that file << y writes the full line to the file.

cin, cout, system не являются однозначными, как убрать ошибки? Вопрос задан 5 лет 11 месяцев назад Изменён 4 года 10 месяцев назад Просмотрен 73k раз Snag the input from std::cin using std::getline(std::cin, strobj) where strobj is a std::string object Use boost::lexical_cast to perform a lexical translation from strobj to either a signed or unsigned integer of largest width (e.g., unsigned long long or something similar) use boost::numeric_cast to cast the integer down to the expected range. How do i use cin for an array asked 7 years, 1 month ago modified 1 year, 8 months ago viewed 78k times

I was taught that you have to use gets(str) to input a string and not cin However i can use cin just fine in the program below Can someone tell me if you can use cin or not Sorry for my bad engl.