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Once that happens, code will resume execution at the catch I think that this only works if you raise and then catch the exception, but not if you try getting the traceback before raising an exception object that you create, which you might want to do in some designs. If there is a breakpoint within a function that's evaluated as part of a when, that breakpoint will suspend execution before any stack unwinding occurs

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By contrast, a breakpoint at a catch will only suspend execution after all finally handlers have run. You explicitly know that your code will return and continue execution instead of halting at the catch block. 22 if there is a hierarchy of exceptions you can use the base class to catch all subclasses of exceptions

In the degenerate case you can catch all java exceptions with:

I want to know if i can safely write catch () only to catch all system.exception types Or do i've to stick to catch (exception) to accomplish this I know for other exception types (e.g. Please forgive my inability to paste the actual code, but what he did was something

Nope, (or ) is 's friend and always there as part of try/catch However, it is perfectly valid to have them empty, like in your example In the comments in your example code (if func1 throws error, try func2), it would seem that what you really want to do is call the next function inside of the block of the previous. Try { webid = new guid(querystring[web])

} catch (formatexception) { webid = guid.empty

} catch (overflowexception) { webid = guid.empty } is there a way to catch both exceptions and only set webid = guid.empty once The given example is rather simple, as it's only a guid, but imagine code where you modify an object multiple times, and if one of the manipulations fails as expected, you. In the following code fragment, is it worthwhile to check for @@error

Will return 1111 ever occur Set xact_abort on begin transaction begin. 0 you can add a return in the catch block