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Is there a possibility that casting a double created via math.round() will still result in a truncated down number no, round() will always round your double to the correct value, and then, it will be cast to an long which will truncate any decimal places. If it's out of range, that'll give an unspecified result so you'll probably want to reduce it the right range first, or assign it to a larger signed type. Had you been doing just double x = a;, you can do away with the explicit conversion since an int is implicitly converted to a double (live example).

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Do you understand the concept of casting If it's in range, just assign it and you're done Casting is the process of type conversion, which is in java very common because its a statically typed language

Static cast is also used to cast pointers to related types, for example casting void* to the appropriate type

Casting conversion is applied to the operand of a cast operator (§15.16) The type of the operand expression must be converted to the type explicitly named by the cast operator. Casting has sense only for a variable (= chunk of memory whose content can change) there are no variables whose content can change, in python There are only objects, that aren't contained in something

They have per se existence Then, the type of an object can't change, afaik Then, casting has no sense in python That's my believing and opinion

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Correct me if i am wrong, please

'casting' with reflection asked 16 years, 1 month ago modified 4 years, 6 months ago viewed 65k times In absence of op's clarification, this question could be interpreted in the sense of converting any string to a number, i.e Turning dog into a number (which of course can be done). The real question is what you want to do when/if the value in the unsigned int it out of the range that can be represented by a signed int

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